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MIT 6.002 Circuits and Electronics, Spring 2007
15 Online
Consider the circuit shown in the figure below, in which RA = 27 and RB = 3 . Tabulate the current through, and the potential difference across, each resistor. https://www.webassign.net/knight/p31-69alt.gif
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first solve Rb parallel to 24 gives 2.66 then that in series with 6 gives 8.66,now you need to solve parallel of 8.66 and 27 which results 2.42 ohms now the overall current is i=24/(4+2.42) =3.73,after this the potential across RA would be v=(3.73*2.42) and that for RB is RB=(9.03*2.66)/(2.66+6) ,similarly apply CDR for current across RA and RB
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