Question

Divide.

Answer 1

is it
\[\frac{ xy^4 }{ 3 }\]

??

Answer 2

Given equation is (x^5y^4/3xy) / (1/x^3y)

We can rewrite this as follows x^5y^4*x^3y / 3xy

Now if we eliminate one x and one y from numerator and denominator we get

x^7y^4/3

Answer 3

Oh! I see what I did wrong! thank you so much!

Answer 4

What about this one? @ganibl

Answer 5

It is also same as above

we can rewrite given equation as (x + 3) (x - 1)/(x^2 - 2x + 1)(x + 3)

x + 3 in numerator and denominator gets cancelled and u will be left out with

x - 1 / x^2 -2x + 1 = x - 1 / (x -1)^2 = 1/x - 1

Answer 6

so \[\frac{ 1 }{ x } - 1\]

Answer 7

Or
\[\frac{ 1 }{ x-1 }\]

@ganibl ??

Answer 8

1/ (x - 1) The second one

Answer 9

okay cool!

Answer 10

What about this?

Answer 11

U can simplify the equations and eliminate the common terms u will get it let me know if u r stuck somewhere