Question

Verify the identity tan x+pi/2 =-cot x
please?

Answer 1

pleaaaaase :)

Answer 2

This would be a good place to start:
\[\tan(x+\frac{ \pi }{ 2 }) = \frac{ \sin(x+\frac{ \pi }{ 2 }) }{ \cos(x+\frac{ \pi }{ 2 }) }\]

Answer 3

how about using the sum identity?

Answer 4

sorry, not necessary

Answer 5

so from what he said don't you have to relate that to -cotx?

Answer 6

DDCamp has it right.

Answer 7

\[\cos \left( x+\frac{\pi}{2} \right)=-\sin x\]
\[\sin \left( x+\frac{\pi}{2} \right)=\cos x\]

Answer 8

\[\cot(x)=\frac{ \cos(x) }{ \sin(x) }\]

Answer 9

and then isn't it a Co-Function Identities like cot= tan(x+pi/2)

Answer 10

oh never mind! Thank you @DDCamp you rock and saved my butt :)

Answer 11

and @pgpilot326 you rock too sorry :D

Answer 12

\[\tan \left( x+\frac{ \pi }{ 2 } \right)=\frac{ \sin \left( x+\frac{ \pi }{ 2 } \right) }{ \cos \left( x+\frac{ \pi }{ 2 } \right)}=\frac{ \cos x }{ -\sin x }=-\cot x\]

Answer 13

lol

Answer 14

@pgpilot326 got it thank you so much :) I'll give the last answer best answer :)

Answer 15

no worries!