Question

How would you go about solving for D

D= e^-3ln10


I know the answer is 10^-3 but i dont see exactly how, thanks

Answer 1

\[-3\ln(10)=\ln(10^{-3})\] is a start

Answer 2

by the property of the log that says \(n\ln(x)=\ln(x^n)\)

Answer 3

then
\[e^{\ln(\spadesuit)}=\spadesuit\] as it is the composition of a function with its inverse

Answer 4

that is why
\[e^{\ln(10^{-3})}=10^{-3}\]

Answer 5

Thanks

Answer 6

yw