Question

solve equation 2a² - 2a =1

Answer 1

Bring the constant term on the right to the left.
Then use the quadratic formula to solve for a.
(Note: the variable "a" used in this equation should not be confused with the "a" term used in the quadratic formula).

Answer 2

confused????

Answer 3

2a^2 - 2a = 1
add -1 to both sides:
2a^2 - 2a - 1 = 0
Use the quadratic formula \[\Large \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a }\]to find the roots.

Answer 4

\[\Large \frac{ -(-2) \pm \sqrt{(-2) ^{2} - 4(2)(-1)} }{ 2(2) } = \frac{ 2 \pm \sqrt{4 + 8} }{ 4 }\] = \[\Large \frac{ 2 \pm \sqrt{12} }{ 4 } = \frac{ 2 \pm \sqrt{4*3} }{ 4 } = \frac{ 2 \pm 2*\sqrt{3} }{ 4 } = \frac{ 1 \pm \sqrt{3} }{ 2 }\]

Answer 5

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Answer 6

The two roots are: (1 + sqrt(3)) / 2 and (1 - sqrt(3)) / 2

You are welcome.