Question

tan of theta= - square root of 3 in radians

Answer 1

is \(-\sqrt3\) in radians?

Answer 2

yes

Answer 3

ok i was just being an retrice making stupid joke
\(-\sqrt3\) is just a number as \(\theta\) is just a number too
the "in radians" part is like saying "in Fahrenheit"

Answer 4

in any case, since
\[\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}\] look for where \(\sin(\theta)=-\frac{\sqrt{3}}{2}\)and \(\cos(\theta)=\frac{1}{2}\) or where \(\sin(\theta)=\frac{\sqrt{3}}{2}\) and \(\cos(\theta)=-\frac{1}{2}\)
there are two such points on the unit circle

Answer 5

look at the unit circle on the last page of the attached cheat sheet
you will see the coordinates \((-\frac{1}{2},\frac{\sqrt3}{2})\) there