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Mathematics 15 Online
OpenStudy (mony01):

differentiate the function...

OpenStudy (mony01):

\[y=(sinx)^{lnx}\]

OpenStudy (anonymous):

you have a choice you can either write \[\large \sin(x)^{\ln(x)}=e^{\ln(x)\ln(\sin(x))}\] and use the chain rule, or you can take the log, get \[\ln(x)\ln(\sin(x))\] find the derivative, and then multiply by the original function all the work is essentially the same, finding the derivative of \[\ln(x)\ln(\sin(x))\] using product rule and chain rule

OpenStudy (mony01):

would the answer be this (ln(sin(x))/x + ln(x)cot(x))(sin(x))^ln(x)

OpenStudy (anonymous):

yes, i think that looks good

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