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differentiate the function...
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\[y=(sinx)^{lnx}\]
you have a choice you can either write \[\large \sin(x)^{\ln(x)}=e^{\ln(x)\ln(\sin(x))}\] and use the chain rule, or you can take the log, get \[\ln(x)\ln(\sin(x))\] find the derivative, and then multiply by the original function all the work is essentially the same, finding the derivative of \[\ln(x)\ln(\sin(x))\] using product rule and chain rule
would the answer be this (ln(sin(x))/x + ln(x)cot(x))(sin(x))^ln(x)
yes, i think that looks good
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