Decide if the statement is always, sometimes, or never true. A quadratic equation has two solutions. A. always B. sometimes C. never
depends on what you mean by \(2\)
Thats the question i got i don't understand the questions so i came here :(
counting multiplicity it always has two if you mean two real solutions, then no it could have no real solutions, one real solution or two real solutions
This is dependent on the value of the discriminant; i.e. the term that appears in the square root of the quadratic formula. If \(ax^2+bx+c\) is our quadratic function, then the discriminant is defined as \(\Delta = b^2-4ac\). Now, we note that if \(\Delta >0\), there's two (unique) solutions, if \(\Delta = 0\), there's one (repeated) solution, and if \(\Delta <0\) there are two imaginary (non real) solutions (i.e. no real solutions).
nice \(\large \Delta\) !!
x^2=1, x = -1, +1 x^2 = -1, x = i , -i yes, sometimes real sometimes imaginary
So that means its B sometimes because depending on the number
i am willing to be that you math teacher wants "sometimes" wouldn't bet more than $7 though
Yes; the moral here is that any quadratic can have at most two solutions.
lol i don't have a teacher my computer is teaching me lol
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