Question

how much work must be done to stop a 1500kg car traveling at 110km/hr?

Answer 1

work must be equal to the kinetic energy of the car:
\[E=mv^2/2\]
you need to convert km/hr to m/s, (x1000/3600)

Answer 2

Yah
\[W = \Delta K = \cancel{K_f}-K_i=-K_i\]

Answer 3

work done=energy.
energy here is kinetic energy because of the presence of velocity.
1st convert 110km/hr to o.11m/s.
2rd E=1/2MV^2.
SO 1/2*1500*(0.11)^2
7500*0.0121
=90.75J

Answer 4

E (kenetic)=1/2 m v^2=w---->E=1/2 (1500 kg)*(1000m/3600s)*110km/h---->W=22.9kj