find the differential solution to the equation to which the given function is the general solution
y=(A+Bx+Cx^2)e^(2x)

Question

find the differential solution to the equation to which the given function is the general solution 
y=(A+Bx+Cx^2)e^(2x)

loser66 · Answer

I don't understand the question. What are we supposed to do?

loser66 · Answer

I guess, you want to find out the function? if so, from your general solution, I expand it to $y= Ae^{2x}+ Bxe^{2x}+Cx^2e^{2x}$
that shows you have $\lambda =2$ triple roots
so, the characteristic equation is $(\lambda -2)^3 =0$
and then $= \lambda^3 -6\lambda^2+12\lambda -8 =0$
that gives us the original function is y''' -6y''+12y' -8y =0
that's all I know. Hope this help

anonymous · Answer

i figure it out thank you 
i was suppose to find the equation 
it was y'''-6y''+8y'-8y=0

loser66 · Answer

12y' , not 8y'

anonymous · Answer

I just seen that thank you

loser66 · Answer

ok

abb0t · Answer

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loser66 · Answer

hihihi.... just stay so long in this site and get "green" . no smart, no knowledge