Find a polar equation for the conic described: The ellipse with a focus at the pole and major axis endpoints of (5,0) and (3, pi)

Question

anonymous · Answer

Cannot draw. Tips when center of mass is no longer above support. 
E.g. square center would be just beyond the horizontal position of its corner.

anonymous · Answer

Huh?....Not a clue what you mean.

anonymous · Answer

Supposed to fit one of the polar forms, though.

zale101 · Answer

oh ok, then nvm sorry

anonymous · Answer

Like $$\frac{ ep }{ 1 \pm esin \theta } or \frac{ ep }{ 1 \pm ecos \theta }$$

zale101 · Answer

i sent u a link, i think it might help u

anonymous · Answer

Glancing it over right now.

anonymous · Answer

Yeah, not enough information to help me out much x_x

zale101 · Answer

@ganeshie8

ganeshie8 · Answer

@ikram002p

ganeshie8 · Answer

lets try,

(5,0) and (3, pi)
major axis on 0, pi => its a horizontal ellipse

anonymous · Answer

Right, I can gather that much, but I dont know how to use that to get e or p or even determine whether it is sin or cos in the equation. Im guessing cos since the angle pi gave a value of 3, but not sure. 

$$\frac{ ep }{ 1 \pm \cos \theta }?$$

anonymous · Answer

Oops
$$r = \frac{ ep }{ 1 \pm ecos \theta }$$

ganeshie8 · Answer

directrix is vertical => its a cos

$\large    r = \frac{ep}{1+ e \cos \theta  }$

ganeshie8 · Answer

we need to find e and p

anonymous · Answer

How can you tell its vertical?

ganeshie8 · Answer

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