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Mathematics 14 Online
OpenStudy (anonymous):

i have a question regarding the cancellation of denominators

OpenStudy (solomonzelman):

yes, what is it?

OpenStudy (tkhunny):

Simple. Never, EVER do anything that could be described like that.

OpenStudy (solomonzelman):

I don't really get that, @tkhunny, are you referring to that the question wasn't written specifically?

Directrix (directrix):

@qtexpress1111 Go ahead and ask your question if you are still online.

OpenStudy (solomonzelman):

He's not.

OpenStudy (solomonzelman):

She, not he, sorry.

OpenStudy (tkhunny):

If someone tells you to "cancel denominators", something is seriously wrong. That's all.

OpenStudy (solomonzelman):

Yeah, I can totally see that, but, by asking a question we can tell her what is the name for whatever that is that she is supposed to do. (Sounds awkward too)

Directrix (directrix):

Not necessarily. We never got the chance to see the OP's question. And, the rest of us don't really know about what you are talking although I think it is a language issue. The Askers here are not scholars. If they were, they would not be on this site. @tkhunny Let us try a little tenderness.

OpenStudy (solomonzelman):

@Directrix is right!

OpenStudy (unklerhaukus):

\[\frac{x}{2}\div\frac y2=\frac xy?\]

OpenStudy (solomonzelman):

Yeah, I also though the question is something like this, @UnkleRhaukus.

OpenStudy (tkhunny):

\(\dfrac{x}{2}\div\dfrac{y}{2} = \dfrac{x}{2}\cdot\dfrac{2}{y} = \dfrac{2}{2}\cdot\dfrac{x}{y} = 1\cdot\dfrac{x}{y} = \dfrac{x}{y}\) Definition of Division of Fractions. Commutative Property of Multiplication. Multiplicative Inverse Property Multiplicative Identity Property There are already sufficient properties to solve such problems. Absolutely no need to invent new ones. I am very much against artificial solutions - very much preferring actual known properties. I realize not everyone agrees with this view.

OpenStudy (solomonzelman):

When I see that, I would just say x/y, not that much of a big deal even for dummies like me.

OpenStudy (unklerhaukus):

assuming y≠0.

OpenStudy (solomonzelman):

Well, to me, it would still be x/y but it would be x/0 see my point?

OpenStudy (tkhunny):

Indeed. I've just never been one to emphasize immediate solution over fundamental understanding of principles. Again, not everyone agrees with this emphasis.

OpenStudy (solomonzelman):

Ok, it just depends on whom the problem is done for, if you see a smarter and more familiar guy, give him a little tip and he will finish it really fast...but for not such smart people....

OpenStudy (unklerhaukus):

@qtexpress1111 i'm still not sure if we have interpreted your question correctly

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