Question

What multiplies to 168 and adds to 74?

Answer 1

[x ^{2}+74x+168=0

Answer 2

xy = 168
x + y =74
you could solve it like this, kinda tedious tho

Answer 3

@shamil98 You have taught me something new!!!

Answer 4

lol, glad to be of some help, i'm still thinking of the numbers from guessing tho

Answer 5

I feel like iI've guessed them all, and because it's online I know that no solution is not the answer

Answer 6

there are no two integers that will do this as far as i can tell

Answer 7

I'm in uni, but when factoring I'm lucky to come up with numbers within the multiplication tables.

Answer 8

yeah the values you get are not whole numbers

Answer 9

do you have answer choices perhaps?

Answer 10

using the quadratic formula you dont get integers

Answer 11

the original problem was:
\[\log _{4}(x+13)=5-\log _{5}(x+61)\]

Answer 12

Ah.

Answer 13

\[\huge \log_4 (x+13) + \log_5(x+61) = 5\]
they aren't the same bases so we can't use that log rule...

Answer 14

that should be a 4 not 5 in front of the (x+61)

Answer 15

oh. that makes it easier lol

Answer 16

my bad

Answer 17

\[\huge \log_4(x+13) + \log_4(x+61) = 5\]
using the rule
\[\huge \log_bM + \log_bN = \log_b(MN)\]

Answer 18

\[\huge \log_4 (x+13)(x+61) = 5\]

Answer 19

And now it's pretty easy.

Answer 20

right, that's when I got \[x ^{2}+74x+793=625 \]

Answer 21

Let (x+13)(x+61) = a
\[\huge \log_4 a = 5\]
using the log rule
\[\huge \log_a x = N --> a^n = x\]

Answer 22

which got me to where I am now

Answer 23

\[\huge (x+13)(x+61) = 4^5\]

Answer 24

\[\huge (x+13)(x+61) = 1024\]

Answer 25

hahaha well im stupid

Answer 26

I think you calculuated wrong lol

Answer 27

I most definitely did, thank you so much!!

Answer 28

Anytime! Glad to be of help.

Answer 29

shamil was faster than me!

Answer 30

lol, I actually learned logs quite recently so it's still fresh in my mind xD

Answer 31

I mean typing!

Answer 32

Oh, that, yeah I got used to writing latex hehe

Answer 33

Still in high school?

Answer 34

Yeah.

Answer 35

I'm in pre-calc, atm, I skipped algebra 2 so I had to learn logs for my class lol, my calculus adventures are just goals for myself , if you're wondering.

Answer 36

Cool. I learned logs long ago...I just utilize their rules in university calculus.