The tables below show solutions for two linear equations. If the two equations make up a system of linear equations, in which quadrant is the solution? Quadrant one Quadrant two Quadrant three Quadrant four
@DemolisionWolf Could you help me on this one? :)
ya, first make the equation for each line from the table
How does i do that? Like I've been on this problem all day!
first can you find the slope between two points of the line on the left?
I don't think so ;/
Ugh I'm Confused
do you see where I get the points: (-10, 0) (-7, 3) from?
Yea
k so, just looking at the x values of each point i have a -10 and a -7 correct?
Correct .
k and if i'm a point -10 and want to go to point -7, then I need to add 3 to -10 -10 + 3 = -7 correct?
Correct.
so the value of 3, we are going to call our 'run' value. the 'run' is used to find the slope. slope, m, = rise/run
we have the 'run' value, so all we need now is the 'rise' value, so with the points, (-10, 0) (-7, 3) , i have a y value of 0 and a y value of 3 to go from 0 to 3, i need to add 3. this 3 becomes our 'rise' value, becuase it is the amount of change in the y direction from the first point to the second point
so, rise=3, run=3 thus slope, m=rise/run = 3/3 = 1 so m=1
I get it!Almost. So what quardant would the solution be placed in?
we are 1/4th of the way done with the problem actually... we need to do the other 3 steps in order for you to be able to answer this question. there isn't any faster way... unless you want to graph it. do you wanna graph it?
do u have graph paper?
No
Let's Continue.
thats ok do you wanna try and find the slope for the other line? use the same method that I used.
I don't know ;/
?
k, pick the first two points and post them up
(-10,0) (7,3) Wouldn't it be in quadrant 2??
the points would be from the table on the right, i'll do the first piont (9, -4) u pick the second point
(-10, 0)
^ is the second point.
(8, 3) is the next point. see how we work down the column on the right? so we have two points: (9, -4) (8, 3) how much does the x value change from 9 to 8? (run) how much does the y value change from -4 to 3? (rise)
Uh, Okay. So the next point is (7,10)
right right, so the next point that is after (8, 3) is (7, 10)
so lets just look at points (9, -4) (8, 3), looking at the x values only, what would I add to 9 to get 8?
1
1, correct, -1 to be exact so, 9 + -1 = 8, correct so -1 is our 'run' value, or our change in x from one pont to the next point. looking at the y values, how do they change from one point to the next?
First 1, and then 7?
correct
so our 'run' is -1 and our 'rise' is 7 slope, m = rise/run = 7/-1 = -7
so for the left side we have m = 1 and for the right column side of the table we got m = -7 now we need to create line equations for each column y=mx+b does this sound familiar?
Ok. So do we know what quardrant it is?
TTP, i'm really sorry this is taking so long, but we are only 1/2 way through all the steps :/ do you wanna keep going or are you 'over' trying to do this?
Keep going!
looking at the right column of the table, we found m = -7 and have 3 points, but we will only look at 1 point, the first point. (9, -4) if I plug in m, x, and y, into the 'slope-intercept' form equation of y = mx+b i get -4 = -7(9) + b correct?
Correct.
so, we need to solve for 'b' -4 = -7(9) + b -4 = -63 + b 59 = b then we re-write the equation: y=mx+b with only the m and b values we have, so m=-7, b=59 y=-7x+59 this is the equation for the line for the points in the right column
can you solve for 'b' in y = mx+b if m = 1 (-10, 0) ?
I don't think so??
thats ok, first plug in the values for m, x, and y in the equation y=mx+b from what I told you in the last post
Mhm
m = 1 (-10, 0) or x=-10, y=0 plug these into: y=mx+b
Could you help? I'm still a little confused??
every where you see an 'm' in the equation y = mx + b, replace it with a 1, becuase m=1 every where you see an 'x', replace it with at -10, because x = -10 everywhere you see a 'y', replace it with a 0, becuase y = 0
* i know there are alot of steps, but we are almost done!!
Yay! Next,
TTP, you gotta help me out here! do this part for me, *atleast try! "every where you see an 'm' in the equation y = mx + b, replace it with a 1, becuase m=1 every where you see an 'x', replace it with at -10, because x = -10 everywhere you see a 'y', replace it with a 0, becuase y = 0
0=1-10+b
Did i do it right?
yep! 0=1(-10)+b we'll put ( ) around the -10, so we know it means multiply
now we solve for b
u wanna take a crack at this step? just give it a try?
I think you know how to do more than you have been leading me to think! be confident in yourself ^_^
I really don't know a whole lot,But i can try! I think B=10?
haha ^_^ great work, b = 10 is correct
Next step :)
:) take the formula y = mx+b and replace all the 'm's with 1, because m=1 and replace all the 'b's with 10, becuase b=10
Okay, so 0=1x+10? Correct?
close, but just replace the 'm' and the 'b' 0=1x+10 should really be y = 1x + 10
So, what do i do next?
so we take the equation: y = 1x + 10 and y=-7x+59 set them equal to each other, so 1x + 10 = -7x + 59 then solve for x, you wanna try?
x=\[49 \over 8\]
Right??
^_^ TTP, you certainly can do more than you have been showing me :D that is correct
so, we have a x value of 49/8 all we need now is a y value, so take the equation: y = 1x + 10 plug in the value for x we just got, and tell me what y equals
this is the very last step ^_^
\[129 \over 8\]
I think?
you are right again ^_^
Yay! High Five! Lol, So are answer is ?
so, we are at the last step, the two lines intersect at the point,\[ (\frac{49}{8} , \frac {129}{8} )\] since both the x and y value are positive, this occurs in which quadrant? |dw:1386746235252:dw|
haha, im usualy the one to say high five!
Quadrant 1
yep! good work!! ^_^
Thank you!!! :)
ur welcome im impressed you stuck with it!!
have a good night ^_^
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