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Mathematics 16 Online
OpenStudy (ttp):

The tables below show solutions for two linear equations. If the two equations make up a system of linear equations, in which quadrant is the solution? Quadrant one Quadrant two Quadrant three Quadrant four

OpenStudy (ttp):

OpenStudy (ttp):

@DemolisionWolf Could you help me on this one? :)

OpenStudy (anonymous):

ya, first make the equation for each line from the table

OpenStudy (ttp):

How does i do that? Like I've been on this problem all day!

OpenStudy (anonymous):

first can you find the slope between two points of the line on the left?

OpenStudy (ttp):

I don't think so ;/

OpenStudy (ttp):

Ugh I'm Confused

OpenStudy (anonymous):

do you see where I get the points: (-10, 0) (-7, 3) from?

OpenStudy (ttp):

Yea

OpenStudy (anonymous):

k so, just looking at the x values of each point i have a -10 and a -7 correct?

OpenStudy (ttp):

Correct .

OpenStudy (anonymous):

k and if i'm a point -10 and want to go to point -7, then I need to add 3 to -10 -10 + 3 = -7 correct?

OpenStudy (ttp):

Correct.

OpenStudy (anonymous):

so the value of 3, we are going to call our 'run' value. the 'run' is used to find the slope. slope, m, = rise/run

OpenStudy (anonymous):

we have the 'run' value, so all we need now is the 'rise' value, so with the points, (-10, 0) (-7, 3) , i have a y value of 0 and a y value of 3 to go from 0 to 3, i need to add 3. this 3 becomes our 'rise' value, becuase it is the amount of change in the y direction from the first point to the second point

OpenStudy (anonymous):

so, rise=3, run=3 thus slope, m=rise/run = 3/3 = 1 so m=1

OpenStudy (ttp):

I get it!Almost. So what quardant would the solution be placed in?

OpenStudy (anonymous):

we are 1/4th of the way done with the problem actually... we need to do the other 3 steps in order for you to be able to answer this question. there isn't any faster way... unless you want to graph it. do you wanna graph it?

OpenStudy (anonymous):

do u have graph paper?

OpenStudy (ttp):

No

OpenStudy (ttp):

Let's Continue.

OpenStudy (anonymous):

thats ok do you wanna try and find the slope for the other line? use the same method that I used.

OpenStudy (ttp):

I don't know ;/

OpenStudy (ttp):

?

OpenStudy (anonymous):

k, pick the first two points and post them up

OpenStudy (ttp):

(-10,0) (7,3) Wouldn't it be in quadrant 2??

OpenStudy (anonymous):

the points would be from the table on the right, i'll do the first piont (9, -4) u pick the second point

OpenStudy (ttp):

(-10, 0)

OpenStudy (ttp):

^ is the second point.

OpenStudy (anonymous):

(8, 3) is the next point. see how we work down the column on the right? so we have two points: (9, -4) (8, 3) how much does the x value change from 9 to 8? (run) how much does the y value change from -4 to 3? (rise)

OpenStudy (ttp):

Uh, Okay. So the next point is (7,10)

OpenStudy (anonymous):

right right, so the next point that is after (8, 3) is (7, 10)

OpenStudy (anonymous):

so lets just look at points (9, -4) (8, 3), looking at the x values only, what would I add to 9 to get 8?

OpenStudy (ttp):

1

OpenStudy (anonymous):

1, correct, -1 to be exact so, 9 + -1 = 8, correct so -1 is our 'run' value, or our change in x from one pont to the next point. looking at the y values, how do they change from one point to the next?

OpenStudy (ttp):

First 1, and then 7?

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

so our 'run' is -1 and our 'rise' is 7 slope, m = rise/run = 7/-1 = -7

OpenStudy (anonymous):

so for the left side we have m = 1 and for the right column side of the table we got m = -7 now we need to create line equations for each column y=mx+b does this sound familiar?

OpenStudy (ttp):

Ok. So do we know what quardrant it is?

OpenStudy (anonymous):

TTP, i'm really sorry this is taking so long, but we are only 1/2 way through all the steps :/ do you wanna keep going or are you 'over' trying to do this?

OpenStudy (ttp):

Keep going!

OpenStudy (anonymous):

looking at the right column of the table, we found m = -7 and have 3 points, but we will only look at 1 point, the first point. (9, -4) if I plug in m, x, and y, into the 'slope-intercept' form equation of y = mx+b i get -4 = -7(9) + b correct?

OpenStudy (ttp):

Correct.

OpenStudy (anonymous):

so, we need to solve for 'b' -4 = -7(9) + b -4 = -63 + b 59 = b then we re-write the equation: y=mx+b with only the m and b values we have, so m=-7, b=59 y=-7x+59 this is the equation for the line for the points in the right column

OpenStudy (anonymous):

can you solve for 'b' in y = mx+b if m = 1 (-10, 0) ?

OpenStudy (ttp):

I don't think so??

OpenStudy (anonymous):

thats ok, first plug in the values for m, x, and y in the equation y=mx+b from what I told you in the last post

OpenStudy (ttp):

Mhm

OpenStudy (anonymous):

m = 1 (-10, 0) or x=-10, y=0 plug these into: y=mx+b

OpenStudy (ttp):

Could you help? I'm still a little confused??

OpenStudy (anonymous):

every where you see an 'm' in the equation y = mx + b, replace it with a 1, becuase m=1 every where you see an 'x', replace it with at -10, because x = -10 everywhere you see a 'y', replace it with a 0, becuase y = 0

OpenStudy (anonymous):

* i know there are alot of steps, but we are almost done!!

OpenStudy (ttp):

Yay! Next,

OpenStudy (anonymous):

TTP, you gotta help me out here! do this part for me, *atleast try! "every where you see an 'm' in the equation y = mx + b, replace it with a 1, becuase m=1 every where you see an 'x', replace it with at -10, because x = -10 everywhere you see a 'y', replace it with a 0, becuase y = 0

OpenStudy (ttp):

0=1-10+b

OpenStudy (ttp):

Did i do it right?

OpenStudy (anonymous):

yep! 0=1(-10)+b we'll put ( ) around the -10, so we know it means multiply

OpenStudy (anonymous):

now we solve for b

OpenStudy (anonymous):

u wanna take a crack at this step? just give it a try?

OpenStudy (anonymous):

I think you know how to do more than you have been leading me to think! be confident in yourself ^_^

OpenStudy (ttp):

I really don't know a whole lot,But i can try! I think B=10?

OpenStudy (anonymous):

haha ^_^ great work, b = 10 is correct

OpenStudy (ttp):

Next step :)

OpenStudy (anonymous):

:) take the formula y = mx+b and replace all the 'm's with 1, because m=1 and replace all the 'b's with 10, becuase b=10

OpenStudy (ttp):

Okay, so 0=1x+10? Correct?

OpenStudy (anonymous):

close, but just replace the 'm' and the 'b' 0=1x+10 should really be y = 1x + 10

OpenStudy (ttp):

So, what do i do next?

OpenStudy (anonymous):

so we take the equation: y = 1x + 10 and y=-7x+59 set them equal to each other, so 1x + 10 = -7x + 59 then solve for x, you wanna try?

OpenStudy (ttp):

x=\[49 \over 8\]

OpenStudy (ttp):

Right??

OpenStudy (anonymous):

^_^ TTP, you certainly can do more than you have been showing me :D that is correct

OpenStudy (anonymous):

so, we have a x value of 49/8 all we need now is a y value, so take the equation: y = 1x + 10 plug in the value for x we just got, and tell me what y equals

OpenStudy (anonymous):

this is the very last step ^_^

OpenStudy (ttp):

\[129 \over 8\]

OpenStudy (ttp):

I think?

OpenStudy (anonymous):

you are right again ^_^

OpenStudy (ttp):

Yay! High Five! Lol, So are answer is ?

OpenStudy (anonymous):

so, we are at the last step, the two lines intersect at the point,\[ (\frac{49}{8} , \frac {129}{8} )\] since both the x and y value are positive, this occurs in which quadrant? |dw:1386746235252:dw|

OpenStudy (anonymous):

haha, im usualy the one to say high five!

OpenStudy (ttp):

Quadrant 1

OpenStudy (anonymous):

yep! good work!! ^_^

OpenStudy (ttp):

Thank you!!! :)

OpenStudy (anonymous):

ur welcome im impressed you stuck with it!!

OpenStudy (anonymous):

have a good night ^_^

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