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Physics 15 Online
OpenStudy (anonymous):

) A 1.62 kg wooden board floats in water with 22.0% of its volume above the surface. a) Calculate the density of the wood. (ans: 0.780 g/cm3) b) How much mass must be placed on the wood to sink it? (ans: 457 g)

OpenStudy (anonymous):

Maybe you need to know the density of water first? I don't know but I think it would help...

OpenStudy (anonymous):

density of water 1g/cm3

OpenStudy (anonymous):

Due to the buoyancy (the fact the board is floating), you know that the weight of the wooden board is equal to the weight of the water that the board displaces. So \[W_{water} = W_{board}\] \[ \rho_{water} V_{displaced} = m_{board}g\] And you know that \[V_{displaced} = .22 V_{board}\]

OpenStudy (anonymous):

also \[ \rho_{water} = 1000kg/m^3\]

OpenStudy (anonymous):

Then \[\rho_{board}=\frac{V_{board}}{m_{board}}\] For the last part, you can find out how much (volumeless) mass is required to sink it again by looking at the first equation, knowing that to sink \[\rho_{water}V_{board} < (m_{board}+M)g\] where M is the mass added

OpenStudy (anonymous):

Make sense? ^_^

OpenStudy (anonymous):

This makes perfect sense. Thank you so much! I was having trouble relating percent to volume.

OpenStudy (anonymous):

Oh, I'm sorry, I made a mistake. The percent volume of the board that's actually displacing water is 1-.22 = .78 . Welcome ^_^ Buoyancy problems are always tricky methinks, especially when things are just given in terms of other values in the problem :P

OpenStudy (anonymous):

oh fortunately that is what i wrote anyway. Hey thanks again man i didn't actually expect to find help on here lol.

OpenStudy (anonymous):

Very welcome - there are lots of helpful folks on this site! ^_^

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