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Mathematics 12 Online
OpenStudy (anonymous):

Already did work, just need to be checked.

OpenStudy (anonymous):

Each penny is 0.75 inches in diameter and 0.061 inches thick. If the cylindrical glass jar containing the pennies has a diameter of 6 inches and a height of 11.5 inches, how many pennies can fit inside the jar? My answer: Cylinder: Diameter-6 in/ Height 11.5 in V=3.14(r²)h 3.14(3²) (11.5) 3.14*9 (11.5) Volume=324.99 Pennies: Diameter-0.75 in/ Height .061 in V=3.14(r²)h 3.14(.375²)(0.061) 3.14*.140625 (.061) 4415625*.061 Volume=0.0269353125 324.99/0.0269353125= 12,065 pennies(approximately) 12,065 Pennies can fit in the cylinder

OpenStudy (anonymous):

y

OpenStudy (anonymous):

@cyter what do you mean y?

OpenStudy (anonymous):

yes

OpenStudy (unklerhaukus):

again, since your value for pi is only accurate to 3 significant figures your final answer can only be accurate to 3 sig figs =12100 pennies (3 sig. figs.)

OpenStudy (anonymous):

@cyter @UnkleRhaukus so it's correct then?

OpenStudy (anonymous):

Only to three decimal places

OpenStudy (unklerhaukus):

yeah i think you have calculated it the right way, [im assuming that you dont have to consider the close packing structure]

OpenStudy (anonymous):

Nah, just how many pennies can fit in there. @UnkleRhaukus is it okay if I give @cyter a medal since I gave you one last time?

OpenStudy (unklerhaukus):

sure, i dont mind

OpenStudy (anonymous):

Thanks for helping, peoplessss!!!! I may be back on here later for more checks :)

OpenStudy (anonymous):

Oh, I have one more question!!

OpenStudy (anonymous):

If you were to find the empty space the pennies leave, would you just subtract the volume of the container from the pennies?

OpenStudy (unklerhaukus):

i think the method we've used assumed no gaps

OpenStudy (anonymous):

yep

OpenStudy (unklerhaukus):

so its not very accurate , (for circles especially) . if the gaps matter you'll have to consider the packing structure,

OpenStudy (unklerhaukus):

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OpenStudy (anonymous):

My guess is that you subtract : 324.99-0.0269353125=324.9630646875 But that doesn't make much since... Well this is what the question states: For the Penny Problem, how much empty space should exist inside the jar after being filled to capacity with pennies? Why doesn't this amount of space actually exist in the jar?

OpenStudy (unklerhaukus):

324.99-0.026935=324.963064 is the volume of the air in the jar with one penny in it

OpenStudy (anonymous):

So just times that by how many pennies you can put in the jar as we figured out in the last problem?

OpenStudy (anonymous):

@UnkleRhaukus ?

OpenStudy (unklerhaukus):

im getting confused, the true number of pennies that will fit will be less than what we calculated because the packing structure has many gaps, the volume of these gaps will be greater than the volume of a penny so the method we used will over estimate the pennies that will fit

OpenStudy (anonymous):

Yeah... I'm way past confused... it's 2:30 am here

OpenStudy (unklerhaukus):

you might have to work out the most pennies that can fit in each layer http://www2.stetson.edu/~efriedma/cirincir/ but if you haven't been studying this stuff maybe there is some other way

OpenStudy (anonymous):

Wow, I don't think we've been studying that... I guess I'll just try and figure this out, and see what my teacher says. Thanks again!

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