Question

if the Kb of weak base is 6.5x10^-6 what is the pH of a 2.5 M solution of this base??
SOMEONE PLEASE HELP ME!!!

Answer 1

so because we know that \[kb=x ^{2}/2.5\]

we can solve for x

\[x=\sqrt{6.5*10^{-6}*2.5}\]

which gives OH concentration.

We can then find ph given that

\[ph=14-(-\log(\left[ OH \right])\]

I hope that helps!!