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A heat engine operates between 500C and 250C. a) Calculate its maximum effeciency. (ans: 32.3%) b) How much heat must be input to produce a work output of 750 J ? (ans: 2320 J)
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a) see Carnot cycle \[\eta=1-T_c/T_h=50\]
that's is what i thought, but the answer provided says answer is 32.3% Also, what about part b?
\[\eta=W/Q\]
using given 23% you will get that Q. but I think 50% is right
sorry 32.2%
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with the information given it has to be 50? must be a mistake
right
hey man thanks I really appreciate your time. just needed some validation.
you are welcome
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