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Mathematics 15 Online
OpenStudy (anonymous):

How many grams of AgNO3 would be needed to prepare 500.0 mL of a 0.250 M AgNO3 solution?

OpenStudy (kc_kennylau):

how heavy is a mole of AgNO3?

OpenStudy (anonymous):

168.85g

OpenStudy (kc_kennylau):

and a quarter of that?

OpenStudy (anonymous):

why a quarter? Im asking because I have to be able to apply this to other problems I have.

OpenStudy (kc_kennylau):

coz 0.25 is a quarter of 1 lol

OpenStudy (anonymous):

so 56.85?

OpenStudy (anonymous):

maryy.jane I believe it goes: molar times volume times molar weight. so 0.25 molar times 0.5 litre times 168.85 grams=21.1063 grams

OpenStudy (anonymous):

You can play with the equations at http://www.graphpad.com/quickcalcs/Molarityform.cfm

OpenStudy (anonymous):

the calculator is cool but um i just don't know how to use it

OpenStudy (anonymous):

Go to the page

OpenStudy (anonymous):

Select the units that best fits the problem. You are working in MOLS and litres so...

OpenStudy (anonymous):

Type in your values ...

OpenStudy (anonymous):

Hit the "Mass=" button and voila!... it also fills in the other equations to show you the basics of getting from anywhere to anywhere else.

OpenStudy (anonymous):

Point is, for your initial question, it is MOLS x LITRES x gms

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