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Mathematics 14 Online
OpenStudy (anonymous):

Factor 3x^2+x-4

OpenStudy (anonymous):

The x in the middle threw me off

OpenStudy (jojo4eva):

(3x+4 )(x-1)

OpenStudy (anonymous):

So don't you have to have it like 3(x+4)(x-1)?

OpenStudy (tkhunny):

If that were an equivalent expression, that would be fine. Unfortunately, \(3(x+4) = 3x + 12 \ne 3x + 4\)

OpenStudy (anonymous):

Oh okay, so I just leave it as (3x+4)(x-1)

OpenStudy (jojo4eva):

yerp

OpenStudy (anonymous):

Okay! Thanks!

OpenStudy (tkhunny):

I'm a little puzzled by your initial comment. There isn't much to factoring without that 'x'-term in the middle. I have to wonder if you are getting the idea. Can you find another one and demonstrate your efforts?

OpenStudy (jojo4eva):

ya @tkhunny thats a good idea

OpenStudy (anonymous):

Yeah...I get the concept, but for some resin I can never find the correct factors. I need help on this one as well: 9x^2+9-18

OpenStudy (anonymous):

I know that 6 and 3 are factors, but I don't know if that will work

OpenStudy (tkhunny):

Assuming this is 9x^2 + 9x - 18, one may wish to start this one by removing the common factors. 9x^2 + 9x - 18 = 9(x^2 + x - 2) There is a whole lot less to explore with only a 2.

OpenStudy (anonymous):

Okay, I get what your saying with that....Thanks ^-^

OpenStudy (tkhunny):

Rather than consider only one factorization, your task is to consider ALL factorizations. For 18, you said 6*3. You should also have noticed 1*18 and 2*9 For 2, well, 1*2 is all you get. If it can be factored, your factored form will look like one of these: (x+1)(x-2) or (x+2)(x-1) Which one works?

OpenStudy (anonymous):

Um, I think (x+1)(x-2)?

OpenStudy (tkhunny):

No good. Prove it! No guessing. Multiply them out and see!

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