Question

can some one help me with chemistry?

Answer 1

@baby1234567 @shrutipande9 @skittlesyum

Answer 2

what

Answer 3

can u help with this?

Answer 4

@smileyylove @stabar @beastly21 @Frostbite @Peter14 @phi

Answer 5

ya what

Answer 6

the questions are posted as files above

Answer 7

I won't answer the questions so I only provide hints:
1) what is chemistry about?
2) think about it as a recipe.
3) do a t0-t1 reaction chart.

Answer 8

ok what about the others?

Answer 9

on number one tyhats not a very good hint not trying to be rude

Answer 10

and you did the wrong hints for the problem number 5 is the one with the chart

Answer 11

Okay. let me ask this way then: In chemistry we burn off lets say methane to carbon dioxide and water. The reaction would be:
CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O
Note that the all the elements are found on both sides.

Answer 12

So what is chemistry about: We make and break bonds between atoms. We don't change the atoms.

Answer 13

so is number one c?

Answer 14

Exactly.

Answer 15

ok awesome

Answer 16

ok so number 2 what did u mean think of it like a recipe?

Answer 17

in number two. we still take the example with the combustion of methane:
CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O
The way to read this is:
1 mole of methane react with 2 moles of oxygen to form 1 mole of carbon dioxide and 2 moles of water.

Answer 18

ok

Answer 19

a?

Answer 20

Ones again perfect.

Answer 21

Imagine each molecule as a ball with a specific mass and try to convise your self that we can not use mass nor volume.

Answer 22

ok now number 3 lol

Answer 23

It is a very poorly question so we do it my way and do my #1 favorite thing: approximate.
Heard of the molar volume before?

Answer 24

yes its how u measure the moles of a substance right?

Answer 25

hello?

Answer 26

Not really. Let me show the calculation and try do your best to understand what I do :)
We assume that we work with ideal gasses! (approximation #1)
\[\Large V(CH _{4})=2.50 l\]
\[\Large n(CH _{4})=\frac{ V(CH _{4}) }{ \sigma }\]
\(\sigma\) is the molar volume and is about 22.41 liters/mol at STP

Answer 27

\[\Large n(H _{2})=4 \times n(CH _{4})\]
Use the molar volume again to find the volume

Answer 28

So the final problem become:
\[\Large V(H _{2})=\sigma \times 4 \times \frac{ V(CH _{4}) }{ \sigma }=4 \times V(CH _{4})\]

Answer 29

See the idea?

Answer 30

yes sorry i was taking my dog out

Answer 31

No problem. :)

Answer 32

ok thanks for the help

Answer 33

You're welcome, if you want help to the rest don't be afraid to ask.

Answer 34

ok well then if thats the case can u help me with the rest lol

Answer 35

and i picked d is that correct?

Answer 36

nm i just finished it igot 100 %
1c
2a
3d
4b
5d
6c
7c

Answer 37

Sounds good, glad you got it 100% and hope you got to understand it so you can do similar problems another time without help! :)

Answer 38

i do i appreciate the help to thanks