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Mathematics 16 Online
OpenStudy (anonymous):

Please need help with a word problem

OpenStudy (anonymous):

It takes Brian 15 hours longer to build a model car than it takes John. If they work together they can build one on 4 hours. Using complete sentences, explain the steps in figuring out how to determine the time it would take Brian to build the car on his own. So if together they are 1/4 and Brian is 1/15x am I going in the right direction?

OpenStudy (amistre64):

b = j+15 is given 1 job = 4 hours = j+b

OpenStudy (amistre64):

so, if j+b can do 1/4 of the job in one hour j+j+15 = 1/4 of the job per hour 2j + 15 = 1/4 per hour

OpenStudy (anonymous):

ok very different from my book mine is more like 1 for numerator equals job 4 equals # of hours for both to complete. it would be the 1/4 less the 1/15x to determine the 1/x of the unknown?????

OpenStudy (amistre64):

the per hour is a bad thought on my part ... 2j hours + 15 hours = 4 hours is what we should prolly be addressing 2j+15 = 4, and this is going negative ....

OpenStudy (amistre64):

if we do this by hourly rates of work \[\frac{1}{b}+\frac{1}{j}=\frac{1}{4}\] \[\frac{1}{j+15}+\frac{1}{j}=\frac{1}{4}\] \[\frac{j+j+15}{j(j+15)}=\frac{1}{4}\] \[4(2j+15)=j^2+15j\]

OpenStudy (amistre64):

\[j^2+7j-60=0\]\[j=\frac{-7+\sqrt{49-4(-60)}}{2}\] j = 5 from that

OpenStudy (anonymous):

holy crap

OpenStudy (amistre64):

lol, right or wrong?

OpenStudy (anonymous):

I was following you right up to the point of how to figure out the equation! This is above my paygrade! If I turn it in they will know I didn't do it myself :)

OpenStudy (amistre64):

quadratic formula ...

OpenStudy (amistre64):

\[ax^2+bx+c=0~:~x=\frac1{2a}(-b\pm\sqrt{b^2-4ac})\]

OpenStudy (anonymous):

yep I got that just didn't know how you got from the equation to it. As u can tell not a math person is y I am here. I stopped at 2x+15/x(x+15=1/4

OpenStudy (amistre64):

"cross multiply" to get it out of fraction mode

OpenStudy (anonymous):

ok that really a lot thank you!!!!

OpenStudy (amistre64):

your welcome

OpenStudy (anonymous):

Is it possible to solve an equation if your denominator is zero? isn't that just an extraneous solution?

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