Mathematics
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OpenStudy (anonymous):
y = -x - 2
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OpenStudy (anonymous):
what is the slope of the following equation?
jimthompson5910 (jim_thompson5910):
hint: y = -x - 2 is really the same as y = -1x - 2
jimthompson5910 (jim_thompson5910):
another hint: y = mx + b has a slope of m
OpenStudy (anonymous):
so the slope of this equation would be -1 ?
jimthompson5910 (jim_thompson5910):
perfect
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OpenStudy (anonymous):
May you help me out with some linear equations and finding the slope by using just the graph ?
jimthompson5910 (jim_thompson5910):
sure I can help
OpenStudy (anonymous):
what is the slope and the y intercept of this graph ?
jimthompson5910 (jim_thompson5910):
pick any point you want on the graph
let's say we pick the point (-2,0)
jimthompson5910 (jim_thompson5910):
how many units must you go up vertically to be at the same level as the next nearest point (on the right)?
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OpenStudy (anonymous):
2 ?
jimthompson5910 (jim_thompson5910):
we start at (-2,0)
the next nearest point on the right is (-1,1)
jimthompson5910 (jim_thompson5910):
how many units must you go upward vertically when you start at (-2,0) and you must be at the same horizontal level as (-1,1)
OpenStudy (anonymous):
1 unit ?
jimthompson5910 (jim_thompson5910):
correct, so the "rise" is 1
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jimthompson5910 (jim_thompson5910):
you've gone up 1 unit
now how many units must you go to the right to land on (-1,1) ?
OpenStudy (anonymous):
1 unit to the right ?
jimthompson5910 (jim_thompson5910):
yep
jimthompson5910 (jim_thompson5910):
the "run" is 1
jimthompson5910 (jim_thompson5910):
so...
slope = rise/run
slope = 1/1
slope = 1
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OpenStudy (anonymous):
thanks bro ! now how do you find the y intercept ?
jimthompson5910 (jim_thompson5910):
the y-intercept is the point where the line crosses the y axis
OpenStudy (anonymous):
so in this case it would be 0,2 ?
jimthompson5910 (jim_thompson5910):
(0,2) yes
jimthompson5910 (jim_thompson5910):
so
slope: m = 2
y-intercept: the point (0,2) which means b = 2
-------------------------
y = mx+b
y = 1x+2
y = x+2 is the equation of this line
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OpenStudy (anonymous):
this was a huge reference thank you again jim_thompson5910!
jimthompson5910 (jim_thompson5910):
you're welcome
OpenStudy (anonymous):
@jim_thompson5910 correct me if im wrong, i got 2/3 as my slope and 0 as my y intercept
jimthompson5910 (jim_thompson5910):
you have the fraction mixed up, it should be 3/2
jimthompson5910 (jim_thompson5910):
the rise is 3 (you go up 3)
the run is 2 (you then go over to the right 2)
slope = rise/run = 3/2
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jimthompson5910 (jim_thompson5910):
the y-intercept is correct though
OpenStudy (anonymous):
thanks jim
jimthompson5910 (jim_thompson5910):
np
OpenStudy (anonymous):
the slope is 1/2 and the y intercept is 0 ?
jimthompson5910 (jim_thompson5910):
now the slope is negative (since as you go from left to right, the line is "falling" or going down)
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jimthompson5910 (jim_thompson5910):
the "rise" in this case is -2 (since you go down 2)
the run is 1
slope = ???
OpenStudy (anonymous):
-2 ?
jimthompson5910 (jim_thompson5910):
yep
jimthompson5910 (jim_thompson5910):
-2/1 = -2
OpenStudy (anonymous):
@jim_thompson5910 Correct ? slope = -4 .y intercept= 1
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jimthompson5910 (jim_thompson5910):
you have the right slope, but the wrong y-intercept
OpenStudy (anonymous):
damn it i used the wrong axis it was 4 right ?
jimthompson5910 (jim_thompson5910):
yes, the y-intercept is 4 or the point (0,4)
jimthompson5910 (jim_thompson5910):
it's always on the y axis
OpenStudy (anonymous):
@jim_thompson5910 thank you. Can you help me find the linear equation of a graph ?
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jimthompson5910 (jim_thompson5910):
what is the slope? what is the y-intercept?
OpenStudy (anonymous):
the slope is 2 and the y intercept is 2
jimthompson5910 (jim_thompson5910):
the slope is incorrect
OpenStudy (anonymous):
1/2
jimthompson5910 (jim_thompson5910):
are you sure it's positive?
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OpenStudy (anonymous):
oops left the (-) sign out sorry
jimthompson5910 (jim_thompson5910):
remember, you're going from left to right
jimthompson5910 (jim_thompson5910):
yep -1/2
jimthompson5910 (jim_thompson5910):
now use y = mx+b
OpenStudy (anonymous):
y=-1/2x+2 ?
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jimthompson5910 (jim_thompson5910):
perfect
OpenStudy (anonymous):
thanks !
jimthompson5910 (jim_thompson5910):
np
OpenStudy (anonymous):
so the linear equation to this graph would be y=-2x
jimthompson5910 (jim_thompson5910):
you are correct, nice job
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OpenStudy (anonymous):
y=1/4x or would it be negative ?
jimthompson5910 (jim_thompson5910):
it's positive, hopefully you see why
OpenStudy (anonymous):
left to right
jimthompson5910 (jim_thompson5910):
yep, start on the left and go to the right
you move UP as you travel along the line
OpenStudy (anonymous):
which of the following points are not on the graph of y=2/3x+1
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jimthompson5910 (jim_thompson5910):
this is the last one I can help you with
OpenStudy (anonymous):
no problem bro