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Mathematics 14 Online
OpenStudy (anonymous):

y = -x - 2

OpenStudy (anonymous):

what is the slope of the following equation?

jimthompson5910 (jim_thompson5910):

hint: y = -x - 2 is really the same as y = -1x - 2

jimthompson5910 (jim_thompson5910):

another hint: y = mx + b has a slope of m

OpenStudy (anonymous):

so the slope of this equation would be -1 ?

jimthompson5910 (jim_thompson5910):

perfect

OpenStudy (anonymous):

May you help me out with some linear equations and finding the slope by using just the graph ?

jimthompson5910 (jim_thompson5910):

sure I can help

OpenStudy (anonymous):

what is the slope and the y intercept of this graph ?

jimthompson5910 (jim_thompson5910):

pick any point you want on the graph let's say we pick the point (-2,0)

jimthompson5910 (jim_thompson5910):

how many units must you go up vertically to be at the same level as the next nearest point (on the right)?

OpenStudy (anonymous):

2 ?

jimthompson5910 (jim_thompson5910):

we start at (-2,0) the next nearest point on the right is (-1,1)

jimthompson5910 (jim_thompson5910):

how many units must you go upward vertically when you start at (-2,0) and you must be at the same horizontal level as (-1,1)

OpenStudy (anonymous):

1 unit ?

jimthompson5910 (jim_thompson5910):

correct, so the "rise" is 1

jimthompson5910 (jim_thompson5910):

you've gone up 1 unit now how many units must you go to the right to land on (-1,1) ?

OpenStudy (anonymous):

1 unit to the right ?

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

the "run" is 1

jimthompson5910 (jim_thompson5910):

so... slope = rise/run slope = 1/1 slope = 1

OpenStudy (anonymous):

thanks bro ! now how do you find the y intercept ?

jimthompson5910 (jim_thompson5910):

the y-intercept is the point where the line crosses the y axis

OpenStudy (anonymous):

so in this case it would be 0,2 ?

jimthompson5910 (jim_thompson5910):

(0,2) yes

jimthompson5910 (jim_thompson5910):

so slope: m = 2 y-intercept: the point (0,2) which means b = 2 ------------------------- y = mx+b y = 1x+2 y = x+2 is the equation of this line

OpenStudy (anonymous):

this was a huge reference thank you again jim_thompson5910!

jimthompson5910 (jim_thompson5910):

you're welcome

OpenStudy (anonymous):

@jim_thompson5910 correct me if im wrong, i got 2/3 as my slope and 0 as my y intercept

jimthompson5910 (jim_thompson5910):

you have the fraction mixed up, it should be 3/2

jimthompson5910 (jim_thompson5910):

the rise is 3 (you go up 3) the run is 2 (you then go over to the right 2) slope = rise/run = 3/2

jimthompson5910 (jim_thompson5910):

the y-intercept is correct though

OpenStudy (anonymous):

thanks jim

jimthompson5910 (jim_thompson5910):

np

OpenStudy (anonymous):

the slope is 1/2 and the y intercept is 0 ?

jimthompson5910 (jim_thompson5910):

now the slope is negative (since as you go from left to right, the line is "falling" or going down)

jimthompson5910 (jim_thompson5910):

the "rise" in this case is -2 (since you go down 2) the run is 1 slope = ???

OpenStudy (anonymous):

-2 ?

jimthompson5910 (jim_thompson5910):

yep

jimthompson5910 (jim_thompson5910):

-2/1 = -2

OpenStudy (anonymous):

@jim_thompson5910 Correct ? slope = -4 .y intercept= 1

jimthompson5910 (jim_thompson5910):

you have the right slope, but the wrong y-intercept

OpenStudy (anonymous):

damn it i used the wrong axis it was 4 right ?

jimthompson5910 (jim_thompson5910):

yes, the y-intercept is 4 or the point (0,4)

jimthompson5910 (jim_thompson5910):

it's always on the y axis

OpenStudy (anonymous):

@jim_thompson5910 thank you. Can you help me find the linear equation of a graph ?

jimthompson5910 (jim_thompson5910):

what is the slope? what is the y-intercept?

OpenStudy (anonymous):

the slope is 2 and the y intercept is 2

jimthompson5910 (jim_thompson5910):

the slope is incorrect

OpenStudy (anonymous):

1/2

jimthompson5910 (jim_thompson5910):

are you sure it's positive?

OpenStudy (anonymous):

oops left the (-) sign out sorry

jimthompson5910 (jim_thompson5910):

remember, you're going from left to right

jimthompson5910 (jim_thompson5910):

yep -1/2

jimthompson5910 (jim_thompson5910):

now use y = mx+b

OpenStudy (anonymous):

y=-1/2x+2 ?

jimthompson5910 (jim_thompson5910):

perfect

OpenStudy (anonymous):

thanks !

jimthompson5910 (jim_thompson5910):

np

OpenStudy (anonymous):

so the linear equation to this graph would be y=-2x

jimthompson5910 (jim_thompson5910):

you are correct, nice job

OpenStudy (anonymous):

y=1/4x or would it be negative ?

jimthompson5910 (jim_thompson5910):

it's positive, hopefully you see why

OpenStudy (anonymous):

left to right

jimthompson5910 (jim_thompson5910):

yep, start on the left and go to the right you move UP as you travel along the line

OpenStudy (anonymous):

which of the following points are not on the graph of y=2/3x+1

jimthompson5910 (jim_thompson5910):

this is the last one I can help you with

OpenStudy (anonymous):

no problem bro

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