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solve for x. 5^(2x)=17
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use logarithms
yeah how
\[\large 5^{2x}=17 \] \[\large \ln 5^{2x}=\ln(17) \] \[\large 2x\ln(5)=\ln(17) \] \[\large 2x=\frac{\ln(17)}{\ln(5)} \] u can finish this
i cant:/
really?
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well \[\large x=\frac{\ln(17)}{2\ln(5)} \]
0.4300
i got 0,880187213865
ohh i see
5^(6x)=220
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i got 0.2729
it is wrong. do what i did and show me your work
i did i got x=log 220/ 6log 5
cool
i got 0,558541536424
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how?
first log 220=2,3424 then log 5=0,6989 this times 6 = 4,1938 then 2,3424 divided by 4,1938 = 0,5585
ohhhh... solve. 7^x=3145
u can do it yourself now, right?
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