how to do equation of circle centered at 5,2 and a radius of 2?

Question

solomonzelman · Answer

$$(x-h)^2+(y-k)^2=r^2$$

solomonzelman · Answer

$$(x-5)^2+(y-2)^2=4$$

anonymous · Answer

so what do you do with the x and y?

solomonzelman · Answer

you don;t do anything with x and y, you just plug in (h,k) inside the formula.

solomonzelman · Answer

$$\huge\color{blue}{(x-h)^2+(y-k)^2=r^2}$$
(h,k)   is  the  center  of  the circle.

anonymous · Answer

ok so the x and y are cancelled out?

solomonzelman · Answer

no, they remain the same, but h and k change into 2 and 5   
and r^2  becomes 4 
because you are substituting the coordinate of the center of the circle and the radius that you are given into the formula.

MAKES SENSE?

anonymous · Answer

yea, thanks. also one quick one also.

anonymous · Answer

what is one similarity between a cylinder and rectangular prism?

solomonzelman · Answer

|dw:1386815561797:dw|
Well really, nothing, other than that they are shapes with a volume or 3D shapes, and both of their volumes would be written in cubic units.

anonymous · Answer

Ok thanks. That was a question my teacher asked me and i couldnt figure it out.

solomonzelman · Answer

Anytime!