Can anyone tell me how to do this problem? It looks really hard! See photo attached. Thanks :o)
Hmm ya this looks tricky D':
@hartnn @satellite73 @Loser66
i figured l'hopital should fit in here somewhere :o) this might even be a published proof but I don't know how to find it unfortunately
out of curiosity what class is this for
the integral has no closed form solution. here's the expansion of the indefinite integral. good luck taking the nth root and the limits. someone is making fun of you. \[x log^n(2)+1/4 x^2 log^(n-1)(2) (n^2-log(4))+1/24 x^3 log^(n-2)(2) (n^4+n^3 (log(2)-1)-4 n^2 log(2)+4 log^2(2))+1/192 x^4 log^(n-3)(2) (n^6+n^5 (log(8)-3) +n^4 (2-9 log(2))+n^3 (log(64)-6 log^2(2))+12 n^2 log^2(2)-8 log^3(2))+(x^5 log^(n-4)(2) (n^8+6 n^7 (log(2)-1)+n^6 (11+3 log^2(2)-26 log(2))-n^5 (6+2 log^3(2)+27 log^2(2)-36 log(2))+16 n^4 log(2) (log(8)-1)+24 n^3 (log(2)-1) log^2(2)-32 n^2 log^3(2)+16 log^4(2)))/1920+(x^6 log^(n-5)(2) (n^10+10 n^9 (log(2)-1)+5 n^8 (7+3 log^2(2)-14 log(2))-5 n^7 (10+2 log^3(2)+21 log^2(2)-34 log(2))+n^6 (24-20 log^3(2)+250 log^2(2)-170 log(2))+10 n^5 log(2) (6+2 log^3(2)+15 log^2(2)-24 log(2))-40 n^4 log^2(2) (log(32)-2)-80 n^3 (log(2)-1) log^3(2)+80 n^2 log^4(2)-32 log^5(2)))/23040+(x^7 log^(n-6)(2) (n^12+15 n^11 (log(2)-1)+n^10 (85+45 log^2(2)-162 log(2))-15 n^9 (15+log^3(2)+26 log^2(2)-43 log(2))+n^8 (274-30 log^4(2)-135 log^3(2)+1275 log^2(2)-1170 log(2))+2 n^7 (-60+8 log^5(2)+75 log^4(2)+435 log^3(2)-975 log^2(2)+480 log(2))+4 n^6 log(2) (-72+15 log^3(2)-400 log^2(2)+345 log(2))-60 n^5 log^2(2) (6+2 log^3(2)+11 log^2(2)-20 log(2))+80 n^4 log^3(2) (log(512)-4)+240 n^3 (log(2)-1) log^4(2)-192 n^2 log^5(2)+64 log^6(2)))/322560+O(x^8)+constant\]
@SinginDaCalc2Blues Still need help?
@Zarkon ?
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