Question

Intervals of decrease:

Answer 1

It is kind of confusing me.

Answer 2

I have been staring at it for a while.

Answer 3

\(f\) is increasing over the intervals where \(f'>0\) i.e. over the intervals where the graph of \(f'\) is above the \(x\) axis

Answer 4

oh it says "decreasing"
no matter, \(f\) is decreasing where \(f'<0\) i.e. where the graph of \(y=f'\) is below the \(x\) axis

Answer 5

So it is decreasing on (1,3) because it is under the x axis?

Answer 6

yes

Answer 7

not to be annoying, but wasn't that easy?

Answer 8

Yes it was! I just needed to know how to do it. My math class is terrible and I have to look up how to do everything because it doesn't explain anything. Haha! Thanks!

Answer 9

Do you know how to find relative minimums?

Answer 10

yes

Answer 11

isn't it where the function equals 0?

Answer 12

as the derivative goes from being positive to negative, i.e. where the derivative crosses the \(x\) axis from above to below, the function goes from increasing to decreasing
that means it has a relative max there

Answer 13

you see from the picture that \(y=f'\) goes from above the \(x\) axis to below at \(x=1\) which means \(f(1)\) is a relative maximum

Answer 14

I have found relative minimums on functions before but I just don't know what to do with the functions that have square roots.

Answer 15

such as?

Answer 16

I have this function and I think I have the right derivative but I don't know how to make it equal to zero

Answer 17

One minute

Answer 18

k