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A long cylindrical rod of radius R has a charge density of ρ = p(r) that is not constant, but only depends on the distance from the rod center. Show that the radial electric field component obeys d(rE)/dr=ρr/ϵ. (Hint: consider the flux through an annular region bounded by r and r + dr )
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Radial electric field an be obtained by using a Gaussian surface, a cylinder within the rod and for which the integral of E times the surface area perpendicular to E equals the enclosed charge divide by epsilon0. Larger r has more enclosed charge but more area.
2 pi r L E = L (1/epsilon0) integral rho(r) 2 pi r dr where rho(r) is the charge density as a function of distance from the axis of the cylinder
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