Question

MEDALS! I'll BECOME A FAN TOO ! ALGEBRA 2 HELP ! :)
In an experiment, a petri dish with a colony of bacteria is exposed to cold temperatures and then warmed again.

Time: 0 1 2 3 4 5 6
Population:5.1 3.03 1.72 1.17 1.38 2.35 4.08

a.find a quadratic model for the data in the table.

b. use the model to estimate the population of bacteria in 9hrs.

Answer 1

1.consider the leading term of the polynomial function. what is the end behavior of the graph?

a.the leading term is -3x^5. since n is odd and a is negative the end behavior is up and up.

b.the leading term is -3x^5. since n is odd and a is negative the end behavior is down and down.

c.the leading term is -3x^5. since n is odd and a is negative the end behavior is up and down

d.the leading term is -3x^5. since n is odd and a is negative the end behavior is down and up

Answer 2

plesseeee help me :)))

Answer 3

Is your second posting related to the first?

Answer 4

Here's a graph of the data

Answer 5

sorry, no they are two seperate questions

Answer 6

so its D. down and then up?
i'll give you a medal if you can help with the 2nd question :)

Answer 7

The graph I posted is for the petri dish question.

Answer 8

For the second question you posted, is that all the information you have?
The question mentions that -3x^5 is the leading term to the polynomial function, which seems to imply there is more to the equation.

Answer 9

oh ok i see. and yes sorry ! here it is
-3x^5+9x^4+5x^3+3

Answer 10

Okay - I think I'll graph that.

Answer 11

I don't think you found the "quadratic model" for the first question ?

Answer 12

or the 2nd one, sorry

Answer 13

oh gosh, I'm confusing myself 1st one quadratic model parts a&B and 2nd one multiple choice abc OR d

Answer 14

are you still there?

Answer 15

I'm still here - graphs take a bit of time.

Here is the data for that graph:
1.00 14.00
0.90 10.78
0.80 8.26
0.70 6.37
0.60 5.01
0.50 4.09
0.40 3.52
0.30 3.20
0.20 3.05
0.10 3.01
0.00 3.00
-0.10 3.00
-0.20 2.98
-0.30 2.95
-0.40 2.94
-0.50 3.03
-0.60 3.32
-0.70 3.95
-0.80 5.11
-0.90 7.03
-1.00 10.00

Answer 16

Thank You for the hard work! thats great!
so 9hrs would be?….

Answer 17

I wasn't able to formulate a quadratic equation for the first question.
Maybe a little more time might do it.

Answer 18

ok sure :) that would be awesome !

Answer 19

I'll give it a try

Answer 20

ok great :) you rock ! I'm gonna give you good testimonial for all your help!

Answer 21

so the question you just answered was for the 2nd, correct ?

Answer 22

hello?

Answer 23

Well, I have the equation from the first question
Y = .38x² -2.45x +5.1

Answer 24

And that long answer was for question 2

Answer 25

oh ok and i got D right?

Answer 26

and now you are solving for the first question parts a&b ?

Answer 27

Using the quadratic formula Y = .38x² -2.45x +5.1 to find the population for 9 hours we get 13.83

(for this we substitute 9 into Y = .38x² -2.45x +5.1 to get 13.83)
This answer contains part a and b of question 1

Answer 28

ok so this is for question 1 and the previous answer with all the data is for question 2? correct? and was i right about it being D?

Answer 29

Yes all that data is for question 2 - but I really think I solved question 1 exactly.

Answer 30

I'm not certain if you are right about D being the answer.

Answer 31

sooo….In an experiment, a petri dish with a colony of bacteria is exposed to cold temperatures and then warmed again.

Time: 0 1 2 3 4 5 6
Population:5.1 3.03 1.72 1.17 1.38 2.35 4.08

a.find a quadratic model for the data in the table.

b. use the model to estimate the population of bacteria in 9hrs.

MATCHESUsing the quadratic formula Y = .38x² -2.45x +5.1 to find the population for 9 hours we get 13.83

(for this we substitute 9 into Y = .38x² -2.45x +5.1 to get 13.83)
This answer contains part a and b of question 1

Answer 32

and
consider the leading term of the polynomial function. what is the end behavior of the graph?

a.the leading term is -3x^5. since n is odd and a is negative the end behavior is up and up.

b.the leading term is -3x^5. since n is odd and a is negative the end behavior is down and down.

c.the leading term is -3x^5. since n is odd and a is negative the end behavior is up and down

d.the leading term is -3x^5. since n is odd and a is negative the end behavior is down and up

MATCHES Here is the data for that graph:
1.00 14.00
0.90 10.78
0.80 8.26
0.70 6.37
0.60 5.01
0.50 4.09
0.40 3.52
0.30 3.20
0.20 3.05
0.10 3.01
0.00 3.00
-0.10 3.00
-0.20 2.98
-0.30 2.95
-0.40 2.94
-0.50 3.03
-0.60 3.32
-0.70 3.95
-0.80 5.11
-0.90 7.03
-1.00 10.00

Answer 33

I think you did it backwards???

Answer 34

I worked from positive to negative? yes

Answer 35

ok so was i correct or not on your answers matching the questions?

Answer 36

its late and I'm nearly having a brain fart with all this math :/

Answer 37

Anyway, you were correct in matching the answers to the questions.
By the way - thanks for the testimonial!

Answer 38

lol ok ! Thank you !!! and np !

Answer 39

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Answer 40

just saw this ! Thank you !