Question

How would one go about taking the derivative of: "2π" (?)
Any and all help is greatly appreciated! :)

Answer 1

0

Answer 2

2 and pi are constants !

Answer 3

derivative of a constant is zero !

Answer 4

derevative of any constant is 0

Answer 5

One of the easiest questions Calculus can ask.

Answer 6

Try not to get confused by these constants dressed up in their fancy tuxedos.
They're just trying to trick you.\[\Large \frac{d}{dx}e^3\quad=\quad 0\]\[\Large \frac{d}{dx}\ln(2)\quad=\quad 0\]\[\Large \frac{d}{dx}2\pi\quad=\quad 0\]There is no variable term present in any of these, so they're all constant.

Answer 7

Thanks for the explanation @zepdrix. You were spot on- I was getting thrown off by the π.
Thanks again !

Answer 8

\[\frac{\mathrm d}{\mathrm dx}(2\pi)=\frac{\mathrm d}{\mathrm dx}(2\pi\cdot x^0)=0\times 2\pi \cdot x^{-1}=0\]

Answer 9

Thank you! :)