Question

2 - √3 divided by 2 +√3. if someone can explain how they did it that would be so helpful!

Answer 1

u know rationalisation?

Answer 2

no im not sure how to figure it out :/

Answer 3

[(2- sqrt3)/(2+sqrt3)]*[(2-sqrt3)/(2-sqrt3)]

[4-4sqrt3+(sqrt3)^2]/[(4-(sqrt3)^2]

(4 - 4sqrt3 + 3)/(4-3)

(7-4sqrt3)/1

7-4sqrt3

Answer 4

Multiply by the conjugate

Answer 5

(2-sqrt3)/(2-sqrt3)

Answer 6

\[\frac{ 2-\sqrt3 }{ 2+\sqrt3 }=\frac{ (2-\sqrt3)^2 }{ 4-3 }\]

Answer 7

\[7-4\sqrt3\]

Answer 8

thanks for all your help. why do you multiply it by 2 - √3 over 2 - √3 though

Answer 9

Because you want to get rid od the square root in the denominator

Answer 10

If you bad 2+ sqrt3 over 2+sqrt3 you will still have sqrt term

Answer 11

Had*

Answer 12

okay got it thanks again youve been very helpful