Question

Find the x-coordinate of each point on the curve where the tangent line is vertical. The given equation is x^3y^2-2x^5y=15. The derivative of that is [y(10x^2-3y)]/[2x(y-x^2)].

Answer 1

You don't need the derivative. Just solve x^3y^2-2x^5y=15 for Y and where the function is undefined is your answer