Suppose you revolve the plane region completely about the given line to sweep out a solid of revolution. Describe the solid and find its volume in terms of pi.
Dear HSM: I encourage you to start writing out for yourself and potential helpers what you already know. For example, this "plane region," a square, has a uniform height of 2 and width of 4. Which method of finding the volume would you be inclined to use for #39? You have at least three to choose from: shells, washers, disks. Which of these would you automatically eliminate up front, and why? Note that #39 can be checked by using the formula for the volume of a right circular cylinder of radius r and height h. I suspect you must use calculus to solve this problem, but the formula just mentioned would serve as a convenient check.
im only in geometry so i dont know how to use calculus
OK: Try looking up the formula for the volume of a right circular cylinder. In Problem #39, the diagram shows you the height of the cylinder, as well as the radius (or diameter, which is twice the radius). What's the next step?
for a cylinder \[V=\pi r^2h\]
if you revolve it around the x axis you get this:|dw:1387034718443:dw| you need to find which one is r and which is h on this drawing
radius =2 height =4
Right on. Good going! Can you now calculate the volume of this (horizontal) cylinder in terms of pi?
\[V=\pi 2^2(4)\] \[V=\pi 4(4)\] \[V=16\pi\]
Yes, HSM, that's the correct result for Problem #39. Take a look at the other problem. What are the relevant r (radius) and h (height) for that one?
ok um how do i rotate it
sorry for having to leave earlier. to rotate it, you pretty much imagine it in your head. if you revolve the 4x2 rectangle about the x-axis it will look like a cylinder. adding picture for emphasis:|dw:1387051726842:dw| black rectangle is revolved around the axis . it will look like above.
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