Question

can someone walk me through this problem vvv

Answer 1

Yeah just type it first XD

Answer 2

\[\frac{ 3v ^{2} }{ 6v ^{2} -30v}\times \frac{ v ^{2}-v-20 }{ 3v ^{2} }\]

Answer 3

Look at what you can cancel
3v^2 top and bottom
Left with v^2 - v - 20 / 6 v ^2 - 30v
Factor both
(v - 5) (v- 4) / 6v (v - 5)
Simply by canceling top and bottom

Answer 4

amistre64

Answer 5

@username is a tag, you simply forgot the @ sign

Answer 6

gotcha my bad lol but is this marcusa guy right? if so I still don't understand completely.

Answer 7

marcus is doing well with it; they are assuming you recall some basic principles

Answer 8

I guess its just the way its written its confusing me but I can see how he got the answer. what about 10/16x-72 x 16x^3-72x^2/8x^2?

Answer 9

might help to read better if you acsii it like:


this over
---- x ------
that there

otherwise it just runs altogether and becomes hard to parse

Answer 10

I have it like that on my worksheet

Answer 11

10 16x^3-72x^2
------- x --------------
16x-72 8x^2

Answer 12

we can undistrbute a common factor, top and bottom

Answer 13

so cancel out 16x - 72 and your left with x^2-x?

Answer 14

lets work it slower ....

16x^3 and 72x^2

8*2xxx 8*9xx

looks to me like that set has 8xx in common

Answer 15

Can't there's a x^2

Answer 16

10 8x^2 (2x - 9)
------- x --------------
16x-72 8x^2

the 8x^2 top to bottom can cancel


10 2x - 9
------- x -------
16x-72 1

Answer 17

so pretty much break it down and cancel out?

Answer 18

yep, thats the strategy

that 16x-72 feels like it can be undistributed as well:

16x and 72
8*2x 8*9

so they have 8 in common


10 2x - 9
------- x -------
8(2x-9) 1

i see that 2x-9 is common top to bottom, so we can cancel them


10/8 is all we have left to play with; which can be reduced like fraction do

Answer 19

let me work it out on paper give me a minute (:

Answer 20

I don't get this crap :l

Answer 21

wait maybe I do its kinda like doin what we did yesterday?

Answer 22

all it really amounts to is playing with "glorified fractions"

when a fraction has the same factors top and bottom, they can be canceled since: k/k = 1

Answer 23

the factoring is what we did yesterday yes. this is just using that technique to find common factor top to bottom is all

Answer 24

well if that's the case how do I get rid of 8(2x-9) and 8x^2(2x-9)?

Answer 25

they look to have an 8 in common

Answer 26

oh, and a 2x-9 as well lol

Answer 27

so x^2 and 10 is left?

Answer 28

if we are still working on this:

10 16x^3-72x^2
------- x --------------
16x-72 8x^2




10 8x^2 (2x-9)
------- x --------------
8(2x-9) 8x^2


\[\frac{10}{8(2x-9)}\times \frac{\cancel{8x^2}(2x-9)}{\cancel{8x^2}}\]

\[\frac{10}{8\bcancel{(2x-9)}}\times \frac{\cancel{8x^2}~\bcancel{(2x-9)}}{\cancel{8x^2}}=\frac{10}{8}\]
\[\frac{10/2}{8/2}=\frac54 \]

Answer 29

bro your like super smart :l

Answer 30

lol, sometimes I can be :)

Answer 31

would you like to be y tutor cause I need help. im goin in to community college in January and I need all the help I can get?!

Answer 32

my*

Answer 33

im not sure I have the time alloted to be a suitable tutor. But I can help out as time permits.

Answer 34

I don't need like 24/7 everyday but sure man but I gtg ill hit you up tomorrow im sure

Answer 35

yeah, tomorrow i got a 2 hour final in the morning and then this terms done :)