Question

given the equation of the like y+10=-(x-15) what is the slope?

Answer 1

First we need to put it in slope-intercept form. that is y=mx+b.
So first distribute the - on the right side. Do you know how to do that?

Answer 2

y+10=-x+15
y=-x+15-10
y=-1x+5
here slope is -1

Answer 3

Zeinas' approach will certainly work, and work fine.

However, simply comparing the given equation to the point-slope form of the equation of a straight line would be faster:

y - t0 = m (x - x0)
y + 10 = -1(x - x0)

It's immediately apparent that m = -1.

Answer 4

That's a nice way to do it @mathmale. I didn't know how to do it like that. I learned something too lol

Answer 5

How did you get 0 on the right side?

Answer 6

Are you referring to the 0 in mathmale's reply?

Answer 7

Yes

Answer 8

He used a simpler way. That is point-slope form. The form is y-y1=m(x-x1). And "m" is the slope. I'm not sure how he got the 0, but he just put the equation in that form. If it would have been
y+10=-(x-15)
The answer would have been the same. -1.

Answer 9

I meant
y+10=-1(x-15)

Answer 10

Mathmale speaking: the standard point-slope form of the equation of a straight line could also be written as y-b = m (x-a), which represents the straight line through the point (a,b) with slope of m.
Instead of (a,b), I used (x0, y0) to represent the given point. What this should read is "x sub 0, y sub 0," or, in other words, the "0" is nothing but a subscript.