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Chemistry 7 Online
OpenStudy (anonymous):

Please help me with sigma bonds. I don't get how to do this at all. The question is attached. I need it explained also, please!

OpenStudy (anonymous):

OpenStudy (aaronq):

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OpenStudy (aaronq):

On carbon: 4 bonds = \(sp^3\), no free p orbitals 3 bonds = \(sp^2\), 1 free p orbital 2 bonds = \(sp\), 2 free p orbitals

OpenStudy (aaronq):

free = unhybridized

OpenStudy (anonymous):

i don't understand the concept of this at all

OpenStudy (anonymous):

how exactly do you come up with the answer? what should you know to get the answer?

OpenStudy (chmvijay):

for this u should no about the hybridization and the when sigma and pie bonds are formed :) and why they are formed :) this all u can understand by stdying the hybridization of atomic orbitals :)

OpenStudy (aaronq):

watch these vids (there are 9) he explains well http://www.youtube.com/watch?v=vKd7q6cdiPo&list=PL97DA688081EF9C45

OpenStudy (anonymous):

Thank you aaron!

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