Question

Someone help???):
Suppose a parabola has an axis of symmetry at x = –7 , a maximum height of 4 and also passes through the point (–6, 0). Write the equation of the parabola in vertex form. Show all work.

Answer 1

Do you know the vertex form?

Answer 2

0 = a(-6 + 7)^2 + 4
a = -4

y = -4(x+7)^2 + 4

Answer 3

@xxferrocixx how did you get that answer? could youu break it down a little bit more?

Answer 4

The maximum height is at 4, and the axis of symetery is at x= -7,
vertex form is
y = a(x-h)^2 + k
\[(h,k) -> (-7,4)\]
Passes at (0,-6)
0 = a(-6+7)^2 + 4
= a => -4
so the parabola is
\[y = -4(x+7)^2 + 4\]

Answer 5

thanks shammy :)