Someone help???):
Suppose a parabola has an axis of symmetry at x = –7 , a maximum height of 4 and also passes through the point (–6, 0). Write the equation of the parabola in vertex form. Show all work.

Question

Someone help???): 
Suppose a parabola has an axis of symmetry at x = –7  , a maximum height of 4 and also passes through the point (–6, 0). Write the equation of the parabola in vertex form. Show all work.

shamil98 · Answer

Do you know the vertex form?

anonymous · Answer

0 = a(-6 + 7)^2 + 4
a = -4

y = -4(x+7)^2 + 4

tester97 · Answer

@xxferrocixx how did you get that answer? could youu break it down a little bit more?

shamil98 · Answer

The maximum height is at 4, and the axis of symetery is at x= -7, 
vertex form is
y = a(x-h)^2 + k 
$$(h,k) -> (-7,4)$$
Passes at (0,-6)
0 = a(-6+7)^2 + 4
 = a  => -4
so the parabola is
$$y =  -4(x+7)^2 + 4$$

tester97 · Answer

thanks shammy :)