Question

Use synthetic division to find the quotient and the remainder. (12x^4 + 5x^3 + 3x^2 - 5)/(x + 1)

Answer 1

\[\large \begin{array}{c|rrrrr}
& 12 & 5 & 3 & 0 & -5\\
-1 & & -12 &7 & -10 & 10 \\
\hline
& 12 & -7 & 10 & -10 & \fbox{5}
\end{array} \]

Answer 2

So the remainder would be 5?

Answer 3

yes

Answer 4

And the quotient is 12, -7, 10, -10, 5?

Answer 5

those r the coefficients, and 5 is the remainder (u said it yourself)

Answer 6

Okay then what is my next step this is the part I am confused on, how to turn the coefficients into the quotient. Thank so much!

Answer 7

see how i ordered the coefficients of the original polynomial.

u have now four coefficients. what is the degree of the polynomial?

Answer 8

4?

Answer 9

no. the degree is 3.

now from right to left the power goes from 3 to zero. so say u had 7, -4, 6, and 1 then the polynomial would be
\[\large 7x^3-4x^2+6x+1 \]

got it?

Answer 10

so
\[12^{3}-7x ^{2}+10x-10\]

Answer 11

yes. very good

Answer 12

Okay awesome thank you so much for your help!

Answer 13

u r very welcome