Question

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Answer 1

Please help <3

Answer 2

@RBauer4

Answer 3

Here, isn't log representative of log (base) 10?

Answer 4

yes it is

Answer 5

So, we have everything we need to calculate the pH then.Simply substitute [H+] with 5.4x10^(-14) and calculate the log of that value. Then, we negate the sign of that resulting value.

Answer 6

is it -14.7 ?

Answer 7

@RBauer4 ;c

Answer 8

@shamil98 do you know this ?

Answer 9

pH = –log[H+]
pH = -log(5.4x10^(-14))
he pretty much explained it for you

Answer 10

I'm not getting any of the answers in my choices

Answer 11

I'm sorry for the delayed response. How are you entering in your numbers into the calculator?

Answer 12

I'm entering it into wolfa ; just like this = -log(5.4x10^(-14))

Answer 13

but kept getting 30.

Answer 14

Wolfram is probably using the natural log instead of log base 10

Answer 15

Can you please let me know what it is ? I'm timed right now ;/

Answer 16

~13.26761

Answer 17

Thank you so much I just used the normal calculator and got that too. i didnt think about lol

Answer 18

Yes, you have to be careful about that.

Answer 19

can you help me in one more ?

Answer 20

I can try. I have to leave real soon. What is it?

Answer 21

What is the percent rate of change in function y= (0.99)^x? determine where the function represents exponential decay.

Answer 22

A. 1% exponential growth
B. 1% exponential decay
C. 10%exponential Growth
D. 0.1% exponential decay

Answer 23

Remember how in that other problem, the percent rate of change was 10% growth per year? What was being raised to the power of x was "1.10" right? Notice how in this case, .99 is raised to the power of x and .99 is less than 1. So, by that reasoning, we can say that the percent of change here represents 1% exponential decay.

Answer 24

You explained it so great. thanks! (:

Answer 25

You're welcome. I'll see you around. I might be on later. Good luck!

Answer 26

Okay I really appreciated the help [: