Question

can some one help here please thank you

When 6.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of H2 can be formed?

2 Al + 6HCl → 2 AlCl3 + 3 H2

Al is the limiting reactant, 9.0 mol H2 can be formed

HCl is the limiting reactant, 6.5 mol H2 can be formed

Al is the limiting reactant, 6.0 mol H2 can be formed

HCl is the limiting reactant, 4.3 mol H2 can be formed

Answer 1

if you have 6 mols of Al react with 13 Mols of HCl the equation is balanced as well. EASY. what u do is use the ratio from the balanced equation so all this equation is saying there is 2Al+6HCl/2AlCl3+3H2 you see so if u have 6 moles of 6Al you just tripled the amount of everything else if you have 6 Al then u need 18HCl/6AlCl3+9H2.. So thers your answer.. for you to react 6mols of Al u need 18mols of HCl but the question states u have only 13mol of HCl so your limiting reactant is 13mol of HCl so Answer is number 4. because if you approximate that 13 is roughly alittle more than half of 6 then you nasewr for how much H2 can be formed is approximately alittle more than double its amount which 4.3 is the only valid answer i see. Thanks. have any other questions let me know

Answer 2

omg my bAD its answer number 2 not 4 typooo 6.5 is the valid answer.. because you have 3 H2 and u have to double that amount..