Dealing with parallel and perpendicular lines, and their slopes. If two lines are parallel, and both of their slopes are 1.5, then I need to know what the two slopes relationship is. I first thought it was that they are both the same. On another question, I have two perpendicular lines. One line has a slope of -2/3, and the line it crosses over has a slope of 1.5. I need to know the relationship between the two slopes of these lines. Please don't just give me an answer, I would appreciate it if you told me how to find the relationship between two slopes.
**I first thought it was that they are both the same.*** that sounds right. parallel lines have identical slopes for perpendicular slopes, you have \[ m_1= -\frac{2}{3} , m_2 = 1.5\] if we write 1.5 as 3/2: \[ m_1= -\frac{2}{3} , m_2 = \frac{3}{2}\] do you see any "pattern" ?
Hm. Is it because they are both the same number, but one is negative? (on the perpendicular one)
2/3 and 3/2 are not the same number. But they are related
OH. Oh, I can see it now. (Haha, I was seeing them as the same number) Are they related because they involve the same numbers?
one is the "flip" of the other. actually the negative "flip" Of course, people don't say flip, they say "negative reciprocal" if one slope is \(m_1\), the slope of its perpendicular is \( m_2= - \frac{1}{m_1} \)
example \[ m_1= -\frac{2}{3} \\ m_2= - \frac{1}{-\frac{2}{3}} \\ m_2= - \frac{1\cdot -\frac{3}{2}}{-\frac{2}{3}\cdot -\frac{3}{2}}= -\frac{ -\frac{3}{2}}{1}= \frac{3}{2}\\ \]
(But I think it's easier to just "flip" -2/3 to -3/2 then negate it, to get 3/2)
Oh! I can understand it now. :D Thank you very much! <3
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