after ___ years, the investment has doubled. APR=8%, compounding periods=quarterly, time to double=?
Compound interest formula: \[\Large A = P(1 + \frac{ r }{ n })^{nt}\] Doubled implies A/P = 2; r = 0.08; n = 4 (compounded quarterly) Solve for t.
how do i do it?
Divide both sides of the formula by P A/P = (1 + r/n)^nt Plug in the values: 2 = (1 + 0.08/4)^(4t) 2 = (1.02)^(4t) take log on both sides: log(2) = log{ (1.02)^(4t) } = 4t * log(1.02) divide both sides by 4log(1.02) log(2) / {4log(1.02) = t or t = log(2) / {4log(1.02) use you calculator to compute the right side and round your answer to two decimal places.
9.99
so, it will be 0.95 years?
\[t = \frac{ \log(2) }{ 4*\log(1.2) } = 8.75 years\]
You may want to double-check on your calculator. But at least it is in the ball park of about 9 years which I was expecting based on the doubling time given by the rule of 72.
okay. thanks
you are welcome.
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