Question

Evaluate the integral
∫0 (top) sqrt(t+1)dt
7 (bottom)

ok

Answer 1

I on't get it. Its soo confusing the way you have it.

Answer 2

I will retype it again

Answer 3

\[\int_7^0\sqrt{t+1}dt\] maybe?

Answer 4

7 is on top 0 is on the bottom. Sorry it was backwards earlier.

Answer 5

You must be in 10 or 11th grade. I am only in 9th lol.

Answer 6

\[\int_0^7\sqrt{t+1}dt\] anti derivative is \[\frac{2}{3}(x+1)^{\frac{3}{2}}\] by the power rule backwards
evaluate at \(7\) and at \(0\) then subtract

Answer 7

Thank you!

Answer 8

yw