you purchase a new car a $31,000 and the value decreases %30 each year. How many years will it take before your car is worth lass than $24,000? less than $5,000?
i figured out the function of the value of the car would be 31,000(.70)^t
a) 31,000(.70)^t = 24,000 b) 31,000(.70)^t = 5,000
yea i got that but i dont know how to find t where its less than $5000
take the log of both sides. log(31,000(.70)^t) = log(5,000) log(31,000)+log(.7^t) = log(5,000) t log(.7) = log(5,000)-log(31,000) t = (log(5,000)-log(31,000))/log(.7)
ohh okay so u want to get the t on one side..so t will equal -.938 (rounded) but how will it be less than 5000 at negative.938 years?
t should be 5.115
t = (log(5,000)-log(31,000))/log(.7) = log(5/31)/log(.7)
ohh okay thought it was 7 not .7 log srry k i get it know so that means at 5.115 years its value is less thank 5000?
at 5.115 years its value is equal to 5000 beyond 5.115 years, its value will be less than 5000 so after 6 years, its value will be less than 5000
okay thank u soo much...helps me 4 my upcoming exam
:)
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