Question

Solve the following integral

Answer 1

\[\int\limits_{}^{}\sqrt{16-x^2}\]

Answer 2

Have you learnt trigo substitution?

Answer 3

we may take \[x=4\sin \theta\] to make it more simplified...

Answer 4

I did that, but my answer isn't coming out to what it should be

Answer 5

\[\int \sqrt{16-(4\sin \theta)^2}d\theta=\int \sqrt{16-16\sin^2\theta} d \theta=4\int\sqrt{1-\sin^2\theta }d\theta =4\int \cos\theta d\theta\\=4(\sin \theta+c) \]