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Chemistry 9 Online
OpenStudy (anonymous):

2.0moles of ammonium chloride

OpenStudy (rina.r):

do u want to find the number of grams?

OpenStudy (anonymous):

Numbers

OpenStudy (rina.r):

numbers of what?

OpenStudy (anonymous):

of molecules

OpenStudy (rina.r):

number of molecules in 2.0moles of ammonium chloride

OpenStudy (rina.r):

For this you need the atomic (molecular) mass of MgCl2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. MgCl2= 95.3 grams 2.00 moles MgCl2 × (95.3 grams) = 190.6 grams MgCl2

OpenStudy (anonymous):

Thank you!

OpenStudy (rina.r):

welcome:)

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