Question

Adding Rational Expressions!

Answer 1

It should be easy, I know. I can't seem to do it though.

Answer 2

@ganeshie8 is there any way you can help me?

Answer 3

start by factoring the denominator first : \(x^2 - 3x -10\)

Answer 4

knw how to factor it ? :)

Answer 5

It would be (x+2) and (x-5) right?

Answer 6

Yes !

Answer 7

\(\large \frac{2x+5}{x^2-3x-10} + \frac{x+1}{x+2}\)

\(\large \frac{2x+5}{(x+2)(x-5)} + \frac{x+1}{x+2}\)

Answer 8

To add fractions, we must have same thing in denominators.
do we have same thing for both fractions in denominators ?

Answer 9

Would the problem look like this?

Answer 10

That's what I think it should look like. :/ I'm not sure though

Answer 11

\(\large \frac{2x+5}{x^2-3x-10} + \frac{x+1}{x+2}\)

\(\large \frac{2x+5}{(x+2)(x-5)} + \frac{x+1}{x+2}\)

\(\large \frac{2x+5}{(x+2)(x-5)} + \frac{(x+1)(x-5)}{(x+2)(x-5)}\)

Answer 12

to make same denominators, oly second fraction we need to multiply (x-5) ok

Answer 13

\(\large \frac{2x+5}{x^2-3x-10} + \frac{x+1}{x+2}\)

\(\large \frac{2x+5}{(x+2)(x-5)} + \frac{x+1}{x+2}\)

\(\large \frac{2x+5}{(x+2)(x-5)} + \frac{(x+1)(x-5)}{(x+2)(x-5)}\)

\(\large \frac{2x+5}{(x+2)(x-5)} + \frac{x^2-5x+x-5}{(x+2)(x-5)}\)

\(\large \frac{2x+5}{(x+2)(x-5)} + \frac{x^2-4x-5}{(x+2)(x-5)}\)

\(\large \frac{2x+5+x^2-4x-5}{(x+2)(x-5)} \)

\(\large \frac{x^2-2x}{(x+2)(x-5)} \)

\(\large \frac{x(x-2)}{(x+2)(x-5)} \)

Answer 14

Enjoy...

Answer 15

@ganeshie8 oh my goodness thank you! That's what kept confusing me, I thought I had to multiply 2x+5 by something. Thanks for putting up with me. (:

Answer 16

np :)) our oly goal when adding fractions is to make denominators same so that we can add the numerators.