Question

Help with math please? :)

Answer 1

2. Explain in complete sentences and demonstrate how to add: (x-5)/2x+(x+1)/2x

3. Perform the subtraction: (x-5)/2x-x/(x+3)
Discuss and identify any possible restrictions that exist in the resulting rational expression.

4. Explain in complete sentences and demonstrate how to multiply: (x-5)/2x∙(x-4)/(x+1)

5. Perform the division and explain your work in complete sentences: (x-5)/2x÷6/(x+3)

Answer 2

2. \[\LARGE \frac{ x-5 }{ 2x }+\frac{ x+1 }{ 2x }\]
3. \[\LARGE \frac{ x-5 }{ 2x }-\frac{ x }{ x+3 }\]
4. \[\LARGE \frac{ x-5 }{ 2x }*\frac{ x-4 }{ x+1 }\]
5. \[\LARGE \frac{ x-5 }{ 2x }\div \frac{ 6 }{ x+3 }\]

Answer 3

2.\[\frac{ x-5+x+1 }{ 2x }=\frac{ 2x-4 }{2x }=\frac{ 2\left( x-2 \right) }{ 2x }=\frac{ x-2 }{ x }\]

Answer 4

3.\[\frac{ x-5 }{ 2x }-\frac{ x }{ x+3 }=\frac{ \left( x-5 \right)\left( x+3 \right)-x*2x }{2x \left( x+3 \right) }\]
solve it

Answer 5

I don't know how to do the top part of the fraction.

Answer 6

\[=\frac{ x*x+3*x-5*x-5*3-2x ^{2} }{ 2x \left( x+3 \right) }\]
\[=\frac{ x ^{2}+3x-5x-15-2x ^{2} }{2x \left( x+3 \right) }=\frac{ -x ^{2}-2x-15 }{ 2x \left( x+3 \right) }\]

Answer 7

4.\[\frac{ x-5 }{ 2x }*\frac{ x-4 }{x+1 }=\frac{ \left( x-5 \right)\left( x-4 \right) }{2x \left( x+1 \right) }\]
\[=\frac{ x ^{2}-5x-4x+20 }{2x \left( x+1 \right) }=\frac{ x ^{2}-9x+20 }{2x \left( x+1 \right) }\]

Answer 8

5.\[\frac{ x-5 }{ 2x }\div \frac{ 6 }{ x+3 }=\frac{ x-5 }{ 2x }\times \frac{ x+3 }{ 6 }=\frac{ x ^{2}+3x-5x-15 }{ 12x }\]
simplify it.