Question

how do i solve this log2 3+log2 x=3

Answer 1

then log2(3x)=3
2^3=3x
8=3x
x=8/3

Answer 2

ok great :)thats what i got

Answer 3

i need help with another one

Answer 4

well using log laws

log(ab) = log(a) + log(b)


\[\log_{2}(3 \times x) = 3\]

which when simplified is

\[\log_{2}(3x) = 3\]

so now raise each side as a power of the base

\[2^{\log_{2}(3x)} = 2^3\]

which simplifies to

3x = 8

now just solve for x

Answer 5

ok just write it

Answer 6

3^2x+2=8 solve for x..

Answer 7

i got -0.15

Answer 8

3^2x=6
ln3^2x=ln6
2x ln3=ln6
2x=ln6/ln3
2x=1.630929754
x=0.815464876

Answer 9

the exponent is 3^(2x+2)

Answer 10

oh, i thought the +2 was out of exponent wait a second

Answer 11

thanks :)

Answer 12

2x+2=ln8/ln3
2x+2=1.892789261
x=-0.053605369

Answer 13

yay perfect :D

Answer 14

thank you :)

Answer 15

you're welcome :)