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Chemistry 19 Online
OpenStudy (anonymous):

If the reaction of 5.75 moles of sodium with excess hydrofluoric acid produced an 86.5% yield of hydrogen gas, what was the actual yield of hydrogen gas? Unbalanced equation: Na + HF “yields”/ NaF + H2 1.66 mol H2 2.49 mol H2 2.88 mol H2 3.33 mol H2

OpenStudy (wolfe8):

First, balance the equation. Then, can you find the amount of H2 theoretically?

OpenStudy (anonymous):

Balanced equation: 2Na +2HF → 2NaF + H molar ratio of Na: H2 is 2:1 5.75-mol Na will theoretically produces 5.75-mol/2 = 2.875-mol H2. The yield is 86.5%, so 2.875-mol x .865 = 2.49-mol H2. Is that right?

OpenStudy (wolfe8):

Looks right to me

OpenStudy (anonymous):

So the answer would be b?

OpenStudy (wolfe8):

Yes. Tell me if it's wrong though.

OpenStudy (anonymous):

It was right

OpenStudy (wolfe8):

Great!

OpenStudy (wolfe8):

You would want to close this question.

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